2n^2-(n+12)(2n+3)=18

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Solution for 2n^2-(n+12)(2n+3)=18 equation: 



2n^2-(n+12)(2n+3)=18

We move all terms to the left:

2n^2-(n+12)(2n+3)-(18)=0

We multiply parentheses ..

2n^2-(+2n^2+3n+24n+36)-18=0

We get rid of parentheses

2n^2-2n^2-3n-24n-36-18=0

We add all the numbers together, and all the variables

-27n-54=0

We move all terms containing n to the left, all other terms to the right

-27n=54

n=54/-27

n=-2

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